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Python Returning the Sum of All Odd Numbers in an Array

 

Python: Returning the Sum of All Odd Numbers

in an Array

Python is a versatile programming language that offers a wide range of functionalities. One of its strengths lies in its ability to manipulate arrays and perform various operations on their elements. In this article, we will focus on a specific task: finding the sum of all odd numbers in an array using Python.

Python return sum all odd numbers of array

Understanding the Problem: Before we delve into the code, let's clarify the problem statement. We are given an array of numbers, and our objective is to calculate the sum of all the odd numbers in the array. An odd number is defined as an integer that is not divisible evenly by 2.

Approach: To solve this problem, we will utilize a simple and straightforward approach. We will iterate through each element in the array, check if it is odd, and if so, add it to a running total. Finally, we will return the sum as the result.

Examples: 

Input : arr[] = {1, 2, 3, 4, 5, 6}

Output :Even index positions sum 9

        Odd index positions sum 12

Explanation: Here, n = 6 so there will be 3 even 

index positions and 3 odd index positions in an array

Even = 1 + 3 + 5 = 9

Odd =  2 + 4 + 6 = 12


Input : arr[] = {10, 20, 30, 40, 50, 60, 70}

Output : Even index positions sum 160

        Odd index positions sum 120

Explanation: Here, n = 7 so there will be 3 odd

index positions and 4 even index positions in an array

Even = 10 + 30 + 50 + 70 = 160

Odd = 20 + 40 + 60 = 120 

Code Explanation: Let's break down the code step-by-step to understand how it works:

Python3

# Python program to find out
# Sum of elements at even and
# odd index positions separately
 
# Function to calculate Sum
def EvenOddSum(a, n):
    even = 0
    odd = 0
    for i in range(n):
 
        # Loop to find even, odd Sum
        if i % 2 == 0:
            even += a[i]
        else:
            odd += a[i]
     
    print ("Even index positions sum ", even)
    print ("Odd index positions sum ", odd)
 
# Driver Function
 
arr = [1, 2, 3, 4, 5, 6]
n = len(arr)
 
EvenOddSum(arr, n)
 

Output:
Even index positions sum 9
Odd index positions sum 12

Explain function for find sum of odd numbers in a array in python:

def sum_odd_numbers(arr): total = 0 # Initialize the total sum as zero for num in arr: # Iterate through each element in the array if num % 2 != 0: # Check if the number is odd total += num # Add the odd number to the total sum return total # Return the sum of all odd numbers

  1. We define a function named sum_odd_numbers that takes an array (arr) as an input parameter.

  2. We initialize a variable total to keep track of the running sum, starting with zero.

  3. We use a for loop to iterate through each element, num, in the given array.

  4. Inside the loop, we use the modulus operator (%) to check if the current number is odd. If the number divided by 2 leaves a remainder (num % 2 != 0), it is odd.

  5. If the number is odd, we add it to the total sum by using the += operator.

  6. After iterating through all the numbers in the array, we return the final value of total, which represents the sum of all the odd numbers.

Conclusion:

In this article, we explored a simple and efficient approach to calculate the sum of all odd numbers in an array using Python. By iterating through each element and checking for oddness, we accumulated the sum using a running total. Python's flexibility and readability make it easy to solve such problems. Remember to test your code with different arrays to ensure it behaves as expected.

By utilizing the code explained above, you can effortlessly compute the sum of all odd numbers in any given array using Python.

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